6a^2+12a-210=0

Solution for 6a^2+12a-210=0 equation:

6a^2+12a-210=0

a = 6; b = 12; c = -210;
Δ = b2-4ac
Δ = 122-4·6·(-210)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-72}{2*6}=\frac{-84}{12}
=-7
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+72}{2*6}=\frac{60}{12}
=5
$